document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39296>Question 39296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve (2x-3)(x+5)(x-7)= 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24746 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since we are multiplying three things to get zero...the ONLY way that happen is if one (or more) equals zero...so from<BR>\n" );
document.write( "(2x-3)(x+5)(x-7)= 0<BR>\n" );
document.write( "2x - 3 = 0 and x  = 3/2<BR>\n" );
document.write( "x + 5 = 0 and x = -5<BR>\n" );
document.write( "x - 7 = 0 and x = 7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );