document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346068>Question 346068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a merchant has coffee worth $20 a pound that she wishes to mix with 90 pounds of coffee worth $60 a pound to get a mixture that can be sold for $30 a pound. How many pounds of the $20 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247447 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> coffee $20 a pound   x lbs<BR>\n" );
document.write( "90 pounds of coffee worth $60 a pound <BR>\n" );
document.write( " mixture x+90 lbs  $30 a pound. <BR>\n" );
document.write( "...<BR>\n" );
document.write( "20x+90*60=30(x+90)<BR>\n" );
document.write( "20x+5400=30x+2700<BR>\n" );
document.write( "30x-20x=5400-2700<BR>\n" );
document.write( "10x=2700<BR>\n" );
document.write( "/10<BR>\n" );
document.write( "x= 2700/10<BR>\n" );
document.write( "x= 270 lbs of $20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );