document.write( "Question 346009: find the inverse of following functions:
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document.write( "(a) f(x)=(x^3 + 5)/(x-3) , x≠3
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document.write( "(b)f(x)=(x^3 - 8)/(x^2 - 4) , x≠±2 \n" );
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Algebra.Com's Answer #247445 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! To find inverses:
\n" ); document.write( "Let's try this out: \n" ); document.write( " \n" ); document.write( "1) Replace function notation: \n" ); document.write( " \n" ); document.write( "2) Swap the x's and y's: \n" ); document.write( " \n" ); document.write( "This is the inverse relation. \n" ); document.write( "3) Solve fo y, if possible. \n" ); document.write( "Multiply both sides by y-3: \n" ); document.write( " \n" ); document.write( "Gather the y terms on one side and everything else on the other side of the equation. I'm going to subtract xy and 5 from each side: \n" ); document.write( " \n" ); document.write( "At this point I don't see a way to solve for y. So the inverse is not a function. \n" ); document.write( " \n" ); document.write( "1) Replace function notation: \n" ); document.write( " \n" ); document.write( "2) Swap the x's and y's: \n" ); document.write( " \n" ); document.write( "This is the inverse relation. \n" ); document.write( "3) Solve for y, if possible \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( "Gather the y terms on one side: \n" ); document.write( " \n" ); document.write( "And again I don't see a way to solve for y. So this inverse in not a finction either. \n" ); document.write( " |