document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346052>Question 346052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist leaves his training base for a morning workout, riding at the rate of 20 mph. One hour later, his support staff leaves the base in a car going 36 mph in the same direction. How long will it take the support staff to catch up with the cyclist once the car leaves the base? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247438 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cyclist speed = 20 mph<BR>\n" );
document.write( "so in 1 hour he is ahead by 20 miles.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "car speed = 36 mph<BR>\n" );
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document.write( "the car atches up 36-20 =16 mph<BR>\n" );
document.write( "they have to catch up 20 miles<BR>\n" );
document.write( "20/16 = time to catch up<BR>\n" );
document.write( "1.25 hours </SPAN>\n" );
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