document.write( "Question 38784: x/2 + y/4 = 1/7
\n" ); document.write( "x/4 + y/6 = 1/4\r
\n" ); document.write( "\n" ); document.write( "solve for x and y
\n" ); document.write( "I got x = 29/49 if this is correct please help me determine y.
\n" ); document.write( "thank you.
\n" ); document.write( "

Algebra.Com's Answer #24743 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
From
\n" ); document.write( "x/2 + y/4 = 1/7
\n" ); document.write( "x/4 + y/6 = 1/4
\n" ); document.write( "we can multiply the bottom one by two and subtract...we get
\n" ); document.write( "x/2 + y/4 = 1/7
\n" ); document.write( "-(x/2 + y/3 = 1/2)
\n" ); document.write( "and then have
\n" ); document.write( "-y/12 = -5/14
\n" ); document.write( "so that
\n" ); document.write( "y = 30/7
\n" ); document.write( "now plug that in to either equation and get
\n" ); document.write( "x/2 + 15/14 = 1/7
\n" ); document.write( "multiply all by 14
\n" ); document.write( "7x + 15 = 2
\n" ); document.write( "7x = -13
\n" ); document.write( "x = -13/7
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