document.write( "Question 38784: x/2 + y/4 = 1/7
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document.write( "x/4 + y/6 = 1/4\r
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document.write( "solve for x and y
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document.write( "I got x = 29/49 if this is correct please help me determine y.
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document.write( "thank you. \n" );
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Algebra.Com's Answer #24743 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! From \n" ); document.write( "x/2 + y/4 = 1/7 \n" ); document.write( "x/4 + y/6 = 1/4 \n" ); document.write( "we can multiply the bottom one by two and subtract...we get \n" ); document.write( "x/2 + y/4 = 1/7 \n" ); document.write( "-(x/2 + y/3 = 1/2) \n" ); document.write( "and then have \n" ); document.write( "-y/12 = -5/14 \n" ); document.write( "so that \n" ); document.write( "y = 30/7 \n" ); document.write( "now plug that in to either equation and get \n" ); document.write( "x/2 + 15/14 = 1/7 \n" ); document.write( "multiply all by 14 \n" ); document.write( "7x + 15 = 2 \n" ); document.write( "7x = -13 \n" ); document.write( "x = -13/7 \n" ); document.write( " |