document.write( "Question 346060: a radiator holds 12 qt of liquid. How many quarts of pure antifreeze and how many quarts of 40% antiffreeze solution must be mixed to fill the radiator with a 50% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #247420 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a radiator holds 12 qt of liquid. How many quarts of pure antifreeze and how many quarts of 40% antiffreeze solution must be mixed to fill the radiator with a 50% antifreeze solution? \n" ); document.write( "------------------ \n" ); document.write( "Equation: \n" ); document.write( "anti + anti = anti \n" ); document.write( "0.40x + 1.0(12-x) = 0.50(12) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "40x + 1200-100x = 50*12 \n" ); document.write( "-80x = -600 \n" ); document.write( "x = 60/8 = 15.2 = 7.5 quarts (amt. of pure antifreeze needed in the mixture) \n" ); document.write( "12-x = 4.5 quarts (amt. of 40% solution needed in the mixture) \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |