document.write( "Question 346060: a radiator holds 12 qt of liquid. How many quarts of pure antifreeze and how many quarts of 40% antiffreeze solution must be mixed to fill the radiator with a 50% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #247420 by stanbon(75887)\"\" \"About 
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a radiator holds 12 qt of liquid. How many quarts of pure antifreeze and how many quarts of 40% antiffreeze solution must be mixed to fill the radiator with a 50% antifreeze solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "anti + anti = anti
\n" ); document.write( "0.40x + 1.0(12-x) = 0.50(12)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "40x + 1200-100x = 50*12
\n" ); document.write( "-80x = -600
\n" ); document.write( "x = 60/8 = 15.2 = 7.5 quarts (amt. of pure antifreeze needed in the mixture)
\n" ); document.write( "12-x = 4.5 quarts (amt. of 40% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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