document.write( "Question 346002: A rectangular sheet of metal is 10 cm longer than it is wide. Squares 5 cm on a side, are cut from the corners of the sheet, and the flaps are bent up to form an open topped box having volume 6 liters. Find the original dimensions of the sheet of metal. \n" ); document.write( "
Algebra.Com's Answer #247405 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = x+10
\n" ); document.write( "5cm is cut from the corners.
\n" ); document.write( "so length & width reduce by 10 cm.
\n" ); document.write( "..
\n" ); document.write( "the width will be x-10
\n" ); document.write( "length will be x+10-10
\n" ); document.write( "height will be 5cm
\n" ); document.write( "...
\n" ); document.write( "x(x-10)*5=6000 1 liter = 1000 cm^3
\n" ); document.write( "5x^2-50x-6000=0
\n" ); document.write( "/5
\n" ); document.write( "x^2-10x-600=0
\n" ); document.write( "x^2-30x+20x-600=0
\n" ); document.write( "x(x-30)+20(x-30)=0
\n" ); document.write( "(x-30)(x+20)=0
\n" ); document.write( "x= 30 the width
\n" ); document.write( "length = 40
\n" ); document.write( "...
\n" ); document.write( "CHECK
\n" ); document.write( "30*40*5= 6000 = 6 liters\r
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