document.write( "Question 4969: an airplane flew for 4.23 hours with a 25.5-km/h tail wind. the return flight against the same wind took 4.97 hours. find the speed of the plain in still air. \n" ); document.write( "
Algebra.Com's Answer #2474 by Abbey(339)\"\" \"About 
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let the rate of airplane on the trip going = x+25.5km
\n" ); document.write( "Let the rate returning =x-25.5km
\n" ); document.write( "the distance is the same both ways,
\n" ); document.write( "using rate*time=distance, we have two equations:
\n" ); document.write( "(x+25.5)*4.23=d
\n" ); document.write( "(x-25.5)*4.97=d
\n" ); document.write( "Set them equal to one another,
\n" ); document.write( "(x+25.5)*4.23= (x-25.5)*4.97\r
\n" ); document.write( "\n" ); document.write( "4.23x+107.865=4.97x-126.735
\n" ); document.write( "subtract 4.23x and add 126.735 to both sides:\r
\n" ); document.write( "\n" ); document.write( "234.6=.74x
\n" ); document.write( "divide by .74\r
\n" ); document.write( "\n" ); document.write( "317.027=x
\n" ); document.write( "the airplane traveled 317.02kmh in still air.
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