document.write( "Question 4969: an airplane flew for 4.23 hours with a 25.5-km/h tail wind. the return flight against the same wind took 4.97 hours. find the speed of the plain in still air. \n" ); document.write( "
Algebra.Com's Answer #2474 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! let the rate of airplane on the trip going = x+25.5km \n" ); document.write( "Let the rate returning =x-25.5km \n" ); document.write( "the distance is the same both ways, \n" ); document.write( "using rate*time=distance, we have two equations: \n" ); document.write( "(x+25.5)*4.23=d \n" ); document.write( "(x-25.5)*4.97=d \n" ); document.write( "Set them equal to one another, \n" ); document.write( "(x+25.5)*4.23= (x-25.5)*4.97\r \n" ); document.write( "\n" ); document.write( "4.23x+107.865=4.97x-126.735 \n" ); document.write( "subtract 4.23x and add 126.735 to both sides:\r \n" ); document.write( "\n" ); document.write( "234.6=.74x \n" ); document.write( "divide by .74\r \n" ); document.write( "\n" ); document.write( "317.027=x \n" ); document.write( "the airplane traveled 317.02kmh in still air. \n" ); document.write( " \n" ); document.write( " |