document.write( "Question 345976: How do I solve the equation 4x^2 = 20. And how do I find the x-intercepts are after I solve the equation. \n" ); document.write( "
Algebra.Com's Answer #247391 by haileytucki(390)![]() ![]() You can put this solution on YOUR website! 4x^(2)=20 IN THIS EQUATION, THE / SIGN STANDS FOR +- AND THE ~ SIGN STANDS FOR THE SQUARE ROOT OF SYMBOL.\r \n" ); document.write( "\n" ); document.write( "Divide each term in the equation by 4. \n" ); document.write( "(4x^(2))/(4)=(20)/(4)\r \n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors. \n" ); document.write( "x^(2)=(20)/(4)\r \n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by simplifying each term. \n" ); document.write( "x^(2)=5\r \n" ); document.write( "\n" ); document.write( "Take the square root of both sides of the equation to eliminate the exponent on the left-hand side. \n" ); document.write( "x=\~(5)\r \n" ); document.write( "\n" ); document.write( "First, substitute in the + portion of the \ to find the first solution. \n" ); document.write( "x=~(5)\r \n" ); document.write( "\n" ); document.write( "Next, substitute in the - portion of the \ to find the second solution. \n" ); document.write( "x=-~(5)\r \n" ); document.write( "\n" ); document.write( "The complete solution is the result of both the + and - portions of the solution. \n" ); document.write( "x=~(5),-~(5)_x=2.24,-2.24 \n" ); document.write( " |