document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345948>Question 345948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train travels a certain distance taking 7 hrs in forward journey, during return yourney increased speed of 12km/hr take the time 5 hrs. What is the distance traveled? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247386 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> both ways the distance traveled  is the same.\r<BR>\n" );
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document.write( "time * speed forward = time * speed on return<BR>\n" );
document.write( "let speed while going be x mph. time = 7 hours<BR>\n" );
document.write( "return speed = x+12. time = 5 hours<BR>\n" );
document.write( "7x=(x+12)*5<BR>\n" );
document.write( "7x=5x+60<BR>\n" );
document.write( "7x-5x=60<BR>\n" );
document.write( "2x=60<BR>\n" );
document.write( "x=30 mph speed  forward<BR>\n" );
document.write( "time = 7 hours<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance = 7*30 = 210 miles </SPAN>\n" );
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