document.write( "Question 345969: One sixth of a number minus one seventh of the same number is 1. What is the number?
\n" ); document.write( "So far I have 1/6x-1/7x=1 \n" ); document.write( "

Algebra.Com's Answer #247383 by haileytucki(390) $\"\"$ $\"About$

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1=(1)/(6)*x-(1)/(7)*x\r
\n" ); document.write( "\n" ); document.write( "Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
\n" ); document.write( "(1)/(6)*x-(1)/(7)*x=1\r
\n" ); document.write( "\n" ); document.write( "Multiply (1)/(6) by x to get (x)/(6).
\n" ); document.write( "(x)/(6)-(1)/(7)*x=1\r
\n" ); document.write( "\n" ); document.write( "Multiply -(1)/(7) by x to get -(x)/(7).
\n" ); document.write( "(x)/(6)-(x)/(7)=1\r
\n" ); document.write( "\n" ); document.write( "Find the LCD (least common denominator) of (x)/(6)-(x)/(7)+1.
\n" ); document.write( "Least common denominator: 42\r
\n" ); document.write( "\n" ); document.write( "Multiply each term in the equation by 42 in order to remove all the denominators from the equation.
\n" ); document.write( "(x)/(6)*42-(x)/(7)*42=1*42\r
\n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common factors.
\n" ); document.write( "x=1*42\r
\n" ); document.write( "\n" ); document.write( "Multiply 1 by 42 to get 42.
\n" ); document.write( "x=42 \n" ); document.write( "

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