document.write( "Question 345966: a radiator contains 8 quarts of fluid, 40% of which is antifreeze. how much fluid should be drained and replaced with pure antifreeze so the new mixture is 60% antifreeze \n" ); document.write( "

Algebra.Com's Answer #247379 by haileytucki(390) $\"\"$ $\"About$

You can put this solution on YOUR website!
We have to figure out what mixture of pure antifreeze must be mixed with 40% antifreeze to give a 60% soln\r
\n" ); document.write( "\n" ); document.write( "let x be the amount of 40% (.4) soln and 6-x be the amount of 100% (1) antifreeze.
\n" ); document.write( "In 6 quarts of 60% antifreeze is 3.6 quarts of pure antifreeze.
\n" ); document.write( "0.4x+6-x=3.6\r
\n" ); document.write( "\n" ); document.write( "Since 0.4x and -x are like terms, add -x to 0.4x to get -0.6x.
\n" ); document.write( "-0.6x+6=3.6\r
\n" ); document.write( "\n" ); document.write( "Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides.
\n" ); document.write( "-0.6x=-6+3.6\r
\n" ); document.write( "\n" ); document.write( "Add 3.6 to -6 to get -2.4.
\n" ); document.write( "-0.6x=-2.4\r
\n" ); document.write( "\n" ); document.write( "Divide each term in the equation by -0.6.
\n" ); document.write( "-(0.6x)/(-0.6)=-(2.4)/(-0.6)\r
\n" ); document.write( "\n" ); document.write( "Cancel the common factor of -0.6.
\n" ); document.write( "x=-(2.4)/(-0.6)\r
\n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by simplifying each term.
\n" ); document.write( "x=4 \n" ); document.write( "

\n" );