document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345966>Question 345966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a radiator contains 8 quarts of fluid, 40% of which is antifreeze. how much fluid should be drained and replaced with pure antifreeze so the new mixture is 60% antifreeze </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247376 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a radiator contains 8 quarts of fluid, 40% of which is antifreeze. how much fluid should be drained and replaced with pure antifreeze so the new mixture is 60% antifreeze<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active - active + active = active<BR>\n" );
document.write( "0.40*8 - 0.40x + 1.00x = 0.60(8)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40*8 - 40x + 100x = 60*8<BR>\n" );
document.write( "60x = 20*8<BR>\n" );
document.write( "x = (1/3)8<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 2 2/3 quarts (amt. of fluid to replace)<BR>\n" );
document.write( "===============================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );