document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345682>Question 345682</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular field whose length is 10 meters longer than its width is to be enclosed with exactly 100 meters of fencing materials.  What are the dimensions of the field?\r<BR>\n" );
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document.write( "I got L= 2w+100 and nothing for with.  I really don't get it.  Please help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247337 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = W + 10\r<BR>\n" );
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document.write( "2L + 2W = 100 ___ substitute the equivalent value for L from the first equation and solve for W\r<BR>\n" );
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document.write( "then substitute the numerical value for W into the first equation and find L </SPAN>\n" );
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