document.write( "Question 39287This question is from textbook beggining algebra
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document.write( ": Original equation= h=-5t^2+25t+80\r
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document.write( "The only part of the height equation that we have not discussed is the constant. You have
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document.write( "probably noticed that the constant is always equal to the initial height of the ball (80 m in
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document.write( "our previous exercises). Now, let’s have you develop a height equation.
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document.write( "A ball is thrown upward from the roof of a building 100 m tall with an initial velocity
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document.write( "of 20 m/s. Use this information for exercises 35 to 38.\r
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document.write( "36. Science and medicine. When will the ball reach a height of 80 m? \n" );
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Algebra.Com's Answer #24726 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! h=-5t^2+25t+100 \n" ); document.write( "Let h=80 and solve for \"t\" as follows: \n" ); document.write( "80=-5t^2+25t+100 \n" ); document.write( "-5t^2+25t+20=0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "t=5.7... seconds is the only practical answer. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |