document.write( "Question 345548: Q1:
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document.write( "A class has 10 male and 20 female students out of which half of the male and half of the females have brown eyes. A person is selected at random,what is the probability that this person is either a female or has brown eyes?\r
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document.write( "Q2:
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document.write( "3 students are in a competition for scholarship.The student A is twice as likely to get scholarship as B and B is twice as likely to get as C.What is the probability that either student A or B will get the scholarship? \n" );
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Algebra.Com's Answer #247230 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of anything is the number of ways that it can happen that you would consider a success divided by the number of ways it can happen total -- successes and failures.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 30 people in the class -- that is the denominator of your fraction. Any one of the 20 females, brown eyes or not, is a success plus that half of the males that have brown eyes. 10 males half of which is 5. So 20 plus 5 is 25 and that is your numerator. Remember to reduce your fraction.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |