document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4967>Question 4967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A canoeist paddled 4 hours with a 6=km/h current to reach a campsite. The return trip against the same current took 10 hours. Find the speed of the canoe in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2472 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the rate of paddling on the trip there = x+6km<BR>\n" );
document.write( "Let the rate returning =x-6km\r<BR>\n" );
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document.write( "the distance is the same both ways,<BR>\n" );
document.write( "using rate*time=distance, we have two equations:<BR>\n" );
document.write( "(x+6)*4=d<BR>\n" );
document.write( "(x-6)*10=d<BR>\n" );
document.write( "Set them equal to one another,<BR>\n" );
document.write( "(x+6)*4=(x-6)*10<BR>\n" );
document.write( "4x+24=10x-60<BR>\n" );
document.write( "subtract 4x and add 60 to both sides:<BR>\n" );
document.write( "84=6x<BR>\n" );
document.write( "divide by 6<BR>\n" );
document.write( "14=x\r<BR>\n" );
document.write( "\n" );
document.write( "the canoe traveled 14mph in still water. </SPAN>\n" );
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