document.write( "Question 345586: Solve by using the substitution method
\n" ); document.write( "x+y=56
\n" ); document.write( "x+3y=56
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Algebra.Com's Answer #247165 by Fombitz(32388)\"\" \"About 
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1.\"x%2By=56\"
\n" ); document.write( "2.\"x%2B3y=56\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"y=56-x\"
\n" ); document.write( "\"3y=168-3x\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"x%2B168-3x=56\"
\n" ); document.write( "\"-2x=-112\"
\n" ); document.write( "\"highlight%28x=56%29\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"56%2By=56\"
\n" ); document.write( "\"highlight%28y=0%29\"
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