document.write( "Question 345496: When my father was 35, I was 6. Now he is twice as old as I am. How old is he?\r
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\n" ); document.write( "\n" ); document.write( "I am stuck!
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Algebra.Com's Answer #247082 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
Hi,
\n" ); document.write( "Note: The father will \"always\" be 29 years older than the child
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\n" ); document.write( "Let F be father's age and C be the age of his child, Now!
\n" ); document.write( "Question states the following to be true:
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\n" ); document.write( "F = 2*C
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\n" ); document.write( "\"C=F-29\"(child 'always' 29 years younger than father)
\n" ); document.write( "\"F=2%2A%28F-29%29\"
\n" ); document.write( "Solve
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\n" ); document.write( "\"F=2%2AF-58%29\" TO SOLVE: Subtract F from & add 58 to both sides of the equation
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\n" ); document.write( "\"highlight%2858%29=F%29\"
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