document.write( "Question 345384: An elephant herd is moving at a rate of 6 mph. a stray ran at 10mph and caught up in five minutes. How long(in hours) did the stray run to catch up and how far did it run?
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Algebra.Com's Answer #247081 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
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\n" ); document.write( "\"5\" minutes=\"5%2F60=1%2F12\" hour
\n" ); document.write( "So the stray ran (\"1%2F12\") hour.
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\n" ); document.write( "\n" ); document.write( "HX is the distance that the herd moved.
\n" ); document.write( "In \"5\" minutes, the herd moved,
\n" ); document.write( "\"HX=6%281%2F12%29=1%2F2\"mile
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\n" ); document.write( "SX is the distance that the stray moved.
\n" ); document.write( "In 5 minutes, the stray moved,
\n" ); document.write( "\"SX=10%281%2F12%29\"
\n" ); document.write( "\"SX=10%2F12=5%2F6\"
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\n" ); document.write( "SH is the distance they were intially separated.
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\n" ); document.write( "\"SH%2BHX=SX\"
\n" ); document.write( "\"SH%2B1%2F2=5%2F6\"
\n" ); document.write( "\"SH=5%2F6-3%2F6\"
\n" ); document.write( "\"SH=2%2F6=1%2F3\" mile
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