document.write( "Question 345483: Hi there, Please could you help with this:
\n" );
document.write( "find the equation of the line that contains points (3,-2, 1) and (1, 1,-3).\r
\n" );
document.write( "\n" );
document.write( "Thankyou muchly \n" );
document.write( "
Algebra.Com's Answer #247067 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( "We find a vector parallel to the line by the method of\r\n" ); document.write( "\"subtracting the coordinates\" of (3,-2, 1) and (1, 1,-3).\r\n" ); document.write( "\r\n" ); document.write( "(1-3)i + (1-(-2))j + (-3-1)k = -2i + 3j - 4k = < -2, 3, -4 >\r\n" ); document.write( "\r\n" ); document.write( "A parametric form of the line is then\r\n" ); document.write( "\r\n" ); document.write( "x = 3 + (-2)t, y = -2 + 3t, z = 1 + t\r\n" ); document.write( "\r\n" ); document.write( "Since the direction vector < -2, 3, -4 > has no 0 coordinates,\r\n" ); document.write( "\r\n" ); document.write( "we can write an equation in symmetric form:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |