document.write( "Question 345483: Hi there, Please could you help with this:
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Algebra.Com's Answer #247067 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We find a vector parallel to the line by the method of\r\n" );
document.write( "\"subtracting the coordinates\" of (3,-2, 1) and (1, 1,-3).\r\n" );
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document.write( "(1-3)i + (1-(-2))j + (-3-1)k = -2i + 3j - 4k = < -2, 3, -4 >\r\n" );
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document.write( "A parametric form of the line is then\r\n" );
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document.write( "x = 3 + (-2)t, y = -2 + 3t, z = 1 + t\r\n" );
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document.write( "Since the direction vector < -2, 3, -4 > has no 0 coordinates,\r\n" );
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document.write( "we can write an equation in symmetric form:\r\n" );
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document.write( "\"%28x-3%29%2F%28-2%29\"\"%22%22=%22%22\"\"%28y-%28-2%29%29%2F3\"\"%22%22=%22%22\"\"%28z-1%29%2F%28-4%29\"\r\n" );
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document.write( "Notice that I said \"a\" parametric or symmetric form, not \"the\" parametric \r\n" );
document.write( "of symmetric form, because neither form is unique.\r\n" );
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document.write( "Edwin
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