document.write( "Question 345450: Factor completely
\n" ); document.write( "24-10a+a^2
\n" ); document.write( "how do I solve this algebra 2 question?
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Algebra.Com's Answer #247062 by mananth(16946)\"\" \"About 
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\n" ); document.write( "24-10a+a^2
\n" ); document.write( "product of 1st term and third term = 24a^2
\n" ); document.write( "split the second term such that when added you get -10a & when multiplied you get 24a^2
\n" ); document.write( "they are 6 & 4
\n" ); document.write( "24-6a-4a +a^2
\n" ); document.write( "6(4-a)-a(4-a)
\n" ); document.write( "(6-a)(4-a)
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