document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345438>Question 345438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have to factorise the following expresson but im not sure how to. <BR>\n" );
document.write( "(x-1)squared-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247045 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (X-1)^(2)-4\r<BR>\n" );
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document.write( "The binomial can be factored using the difference of squares formula, because both terms are perfect squares.  The difference of squares formula is X^(2)-b^(2)=(X-b)(X+b).<BR>\n" );
document.write( "((X-1)-2)((X-1)+2)\r<BR>\n" );
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document.write( "Remove the parentheses around the expression X-1.<BR>\n" );
document.write( "(X-1-2)((X-1)+2)\r<BR>\n" );
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document.write( "Subtract 2 from -1 to get -3.<BR>\n" );
document.write( "(X-3)((X-1)+2)\r<BR>\n" );
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document.write( "Remove the parentheses around the expression X-1.<BR>\n" );
document.write( "(X-3)(X-1+2)\r<BR>\n" );
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document.write( "Add 2 to -1 to get 1.<BR>\n" );
document.write( "(X-3)(X+1) </SPAN>\n" );
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