document.write( "Question 345424: In a chemistry class,8 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed? How to solve this problem? \n" ); document.write( "
Algebra.Com's Answer #247023 by haileytucki(390)![]() ![]() You can put this solution on YOUR website! (salt I end up with)/(total liters of solution) = 4% \n" ); document.write( "8 milliliters of 6% saline solution has .06*8=.48 ml salt \n" ); document.write( "Let w = ml of water to be added \n" ); document.write( "so.... \n" ); document.write( "(0.48)/(8+w)=0.04\r \n" ); document.write( "\n" ); document.write( "Since the variable is in the denominator on the left-hand side of the equation, this can be solved as a ratio. For example, (A)/(B)=C is equivalent to (A)/(C)=B. \n" ); document.write( "(0.48)/(0.04)=(w+8)\r \n" ); document.write( "\n" ); document.write( "Since w is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. \n" ); document.write( "(w+8)=(0.48)/(0.04)\r \n" ); document.write( "\n" ); document.write( "Remove the parentheses around the expression w+8. \n" ); document.write( "w+8=(0.48)/(0.04)\r \n" ); document.write( "\n" ); document.write( "Reduce the expression (0.48)/(0.04) by removing a factor of from the numerator and denominator. \n" ); document.write( "w+8=12\r \n" ); document.write( "\n" ); document.write( "Since 8 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 8 from both sides. \n" ); document.write( "w=-8+12\r \n" ); document.write( "\n" ); document.write( "Add 12 to -8 to get 4. \n" ); document.write( "w=4 liters \n" ); document.write( " |