document.write( "Question 345410: How much of an alloy that is 20% copper should be mixed with 200 ounces of an alloy that is 50% copper in order to get an alloy that is 30% copper? \n" ); document.write( "
Algebra.Com's Answer #247015 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 20% alloy.
\n" ); document.write( "\"20A%2B50%28200%29=30%28A%2B200%29\"
\n" ); document.write( "\"20A%2B1000=30A%2B600\"
\n" ); document.write( "\"10A=400\"
\n" ); document.write( "\"A=40\"
\n" ); document.write( "40 ounces of 20% copper are needed.
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