document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38930>Question 38930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find an equation of the hyberbola centered at the origin that has a focus at (square root of 5,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24700 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find an equation of the hyberbola centered at the origin that has a focus at (square root of 5,0)<BR>\n" );
document.write( "SEE THE FOLLOWING EXAMPLE FOR DETAILED ANALYSIS.<BR>\n" );
document.write( "TAKE EQN.AS X^2/A^2-Y^2/B^2=1..............................I<BR>\n" );
document.write( "GIVEN DATA IS INSUFFICIENT TO FIND AN UNIQUE HYPERBOLA..YOU CAN OFCOURSE GIVE EQN.OF ANY HYPERBOLA SATISFYING THESE CONDITIONS.<BR>\n" );
document.write( "AE=5 HERE..TAKE ANY SET OF VALUES WITH E>1 SATISFYING THE ABOVE EQN.SAY A=2.5 AND E=2...FIND B FROM EQN.<BR>\n" );
document.write( "E=SQRT(A^2+B^2)/A^2  ...SUBSTITUTE A AND B IN EQN.I TO GET THE ANSWER.BUT CHECK THE PROBLEM AGAIN<BR>\n" );
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document.write( "Write the equation of a hyperbola from the given information. Graph the equation. Place the center of the hyperbola at the orgin of the coordinate plane. One focus is located at (0,6); one vertex at (0,-(square root) 7<BR>\n" );
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document.write( "THE EQN. OF A HYPERBOLA IN STD.FORM IS<BR>\n" );
document.write( "(X-H)^2/A^2 - (Y-K)^2/B^2=-1….<BR>\n" );
document.write( "WHERE<BR>\n" );
document.write( "(H,K) IS CENTRE…HERE WE HAVE CENTRE IS (0,0).SO H=K=0<BR>\n" );
document.write( "VERTICES ARE (0,B),(0,-B)...B=SQRT(7)<BR>\n" );
document.write( "FOCI ARE (H,K+BE)AND (H,K-BE),THAT IS (0,BE),(0,-BE)....THEY ARE (0,6) AND (0,-6) SINCE CENTRE IS ORIGIN.HENCE BE=6.......E=6/SQRT(7)<BR>\n" );
document.write( "E^2=36/7=(A^2+B^2)/B^2=(A^2+7)/7<BR>\n" );
document.write( "A^2+7=36....A^2=29<BR>\n" );
document.write( "HENCE EQN.IS<BR>\n" );
document.write( "X^2/29-Y^2/7=-1...OR....Y^2/7-X^2/29=1 </SPAN>\n" );
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