document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345376>Question 345376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the ratio of the measure of the complement of angle G to the measure of the supplement of the complement of angle G is 1:4<BR>\n" );
document.write( "find the ratio of the measure of angle G to the supplement og angle G<BR>\n" );
document.write( "use algebra to show your work<BR>\n" );
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document.write( "  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246970 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let measure of G be x<BR>\n" );
document.write( "complement will be 90-x<BR>\n" );
document.write( "supplement of complement will be 180-(90-x)<BR>\n" );
document.write( "=90+x<BR>\n" );
document.write( "....<BR>\n" );
document.write( "ratio = (90-x)/(90+x)= 1/4 <BR>\n" );
document.write( "4(90-x)=90+x<BR>\n" );
document.write( "360-4x=90+x<BR>\n" );
document.write( "add 4x<BR>\n" );
document.write( "360-4x+4x=90+x+4x<BR>\n" );
document.write( "360=90+5x<BR>\n" );
document.write( "add -90<BR>\n" );
document.write( "360-90==5x<BR>\n" );
document.write( "270=5x<BR>\n" );
document.write( "divide by 5<BR>\n" );
document.write( "54 = x   measure of G<BR>\n" );
document.write( "supplement of G = 180-54 = 126<BR>\n" );
document.write( "Ratio = 54/126<BR>\n" );
document.write( "=3/7 </SPAN>\n" );
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