document.write( "Question 345357: Two people are sitting 15 ft apart on a seesaw. One person wighs 120 lbs. The second person weighs 180 lbs. How far from the 120 lb person should the fulcrum be placed so that the seesaw balances? \n" ); document.write( "
Algebra.Com's Answer #246968 by mananth(16946)![]() ![]() You can put this solution on YOUR website! l1 * d1 = l2*d2 \n" ); document.write( "l1*180=l2*120 \n" ); document.write( "l1/l2 = 120/180 \n" ); document.write( "l1/l2=2/3 \n" ); document.write( "... \n" ); document.write( "Total distance = 15 feet \n" ); document.write( "5 parts \n" ); document.write( "one part is 15/5 = 3 feet \n" ); document.write( "l 2= 3 parts \n" ); document.write( "3*3=9 \n" ); document.write( "9 feet from the fulcrum. \n" ); document.write( " |