document.write( "Question 345357: Two people are sitting 15 ft apart on a seesaw. One person wighs 120 lbs. The second person weighs 180 lbs. How far from the 120 lb person should the fulcrum be placed so that the seesaw balances? \n" ); document.write( "
Algebra.Com's Answer #246968 by mananth(16946)\"\" \"About 
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l1 * d1 = l2*d2
\n" ); document.write( "l1*180=l2*120
\n" ); document.write( "l1/l2 = 120/180
\n" ); document.write( "l1/l2=2/3
\n" ); document.write( "...
\n" ); document.write( "Total distance = 15 feet
\n" ); document.write( "5 parts
\n" ); document.write( "one part is 15/5 = 3 feet
\n" ); document.write( "l 2= 3 parts
\n" ); document.write( "3*3=9
\n" ); document.write( "9 feet from the fulcrum.
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