document.write( "Question 345359: Solve in inequality of (4x - 2)/7 < x + 1 and write it in inverval notation \n" ); document.write( "
Algebra.Com's Answer #246956 by mananth(16949) You can put this solution on YOUR website! (4x - 2)/7 < x + 1 \n" ); document.write( "multiply by 7 \n" ); document.write( "(4x-2)/7 * 7 <7(x+1) \n" ); document.write( "4x-2<7x+7 \n" ); document.write( "+2 \n" ); document.write( "4x<7x+7+2 \n" ); document.write( "4x<7x+9 \n" ); document.write( "add -7x \n" ); document.write( "4x-7x<7x-7x+9 \n" ); document.write( "-3x<9 \n" ); document.write( "/-3 \n" ); document.write( "x>-3 \n" ); document.write( "... \n" ); document.write( "(-3,OO) \n" ); document.write( " |