document.write( "Question 345359: Solve in inequality of (4x - 2)/7 < x + 1 and write it in inverval notation \n" ); document.write( "
Algebra.Com's Answer #246956 by mananth(16949)\"\" \"About 
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(4x - 2)/7 < x + 1
\n" ); document.write( "multiply by 7
\n" ); document.write( "(4x-2)/7 * 7 <7(x+1)
\n" ); document.write( "4x-2<7x+7
\n" ); document.write( "+2
\n" ); document.write( "4x<7x+7+2
\n" ); document.write( "4x<7x+9
\n" ); document.write( "add -7x
\n" ); document.write( "4x-7x<7x-7x+9
\n" ); document.write( "-3x<9
\n" ); document.write( "/-3
\n" ); document.write( "x>-3
\n" ); document.write( "...
\n" ); document.write( "(-3,OO)
\n" ); document.write( "
\n" );