document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39018>Question 39018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find all values of w satisfying the equation:\r<BR>\n" );
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document.write( "3w/w-2 = -27/w^2 - 8w + 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24692 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we multiply the left side of<BR>\n" );
document.write( "3w/w-2 = -27/w^2 - 8w + 12<BR>\n" );
document.write( "by (w-6)/(w-6) we can get the denominators to be equal...<BR>\n" );
document.write( "3w(w-6)/(w-2)(w-6) = -27/w^2 - 8w + 12<BR>\n" );
document.write( "and thus<BR>\n" );
document.write( "3w(w-6) = -27  divide both sides by 3 and solve<BR>\n" );
document.write( "w(w-6) = -9<BR>\n" );
document.write( "w^2 - 6w + 9 = 0<BR>\n" );
document.write( "(w - 3)^2 = 0<BR>\n" );
document.write( "w = 3 </SPAN>\n" );
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