document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345258>Question 345258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving 1/6 minus x/3 < 1/2 need to solve for x. I'm not sure how to solve this with the x variable. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246912 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/6-x/3<1/2<BR>\n" );
document.write( "-x/3<1/2-1/6<BR>\n" );
document.write( "-x/3<3/6-1/6<BR>\n" );
document.write( "-x/3<2/6<BR>\n" );
document.write( "-x<2/6*1/3<BR>\n" );
document.write( "-x<2/18<BR>\n" );
document.write( "x>-1/9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );