document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=345204>Question 345204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> line CA bisects angle BCF\r<BR>\n" );
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document.write( "measure of angle ACF =(1/2x+6)\r<BR>\n" );
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document.write( "measure of angle BCF = x^2\r<BR>\n" );
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document.write( "find the measure of angle BCF and the measure of angle ACF </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246879 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ACF =(1/2x+6)<BR>\n" );
document.write( "BCF = x^2<BR>\n" );
document.write( "BCF=2(x/2+6)<BR>\n" );
document.write( "x^2=2(x/2+6)<BR>\n" );
document.write( "x^2=x+12<BR>\n" );
document.write( "x^2-x-12=0<BR>\n" );
document.write( "(x-4)(x+3)=0<BR>\n" );
document.write( "x-4=0<BR>\n" );
document.write( "x=4 <BR>\n" );
document.write( "ACF=4/2+6=2+6=8 DEGREES.<BR>\n" );
document.write( "BCF=4^2=16 DEGREES.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "4^2=2(4/2+6)<BR>\n" );
document.write( "16=2(2+6)<BR>\n" );
document.write( "16=2*8<BR>\n" );
document.write( "16=16  <BR>\n" );
document.write( " </SPAN>\n" );
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