document.write( "Question 345042: Each leg of an isosceles triangle exceeds twice the base by 5 inches. Find each side of the triangle if the perimeter is 5 feet. \n" ); document.write( "
Algebra.Com's Answer #246856 by ankor@dixie-net.com(22740)\"\" \"About 
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Each leg of an isosceles triangle exceeds twice the base by 5 inches.
\n" ); document.write( " Find each side of the triangle if the perimeter is 5 feet.
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\n" ); document.write( "Change 5 ft to 60 inches
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\n" ); document.write( "Let b = length of the base
\n" ); document.write( "then
\n" ); document.write( "(2b+5) = the other two sides
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\n" ); document.write( "The perimeter:
\n" ); document.write( "2(2b+5) = b = 60
\n" ); document.write( "4b + 10 + b = 60
\n" ); document.write( "4b + b = 60 - 10
\n" ); document.write( "5b = 50
\n" ); document.write( "b = \"50%2F5\"
\n" ); document.write( "b = 10 inches is the base
\n" ); document.write( "and
\n" ); document.write( "2(10) + 5 = 25 inches are the other two sides
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\n" ); document.write( "\n" ); document.write( "Check, find the perimeter: 25 + 25 + 10 = 60 inches
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