document.write( "Question 345078: Find a polynomial for the perimeter and for the area.
\n" ); document.write( "z+2 is the width on the top of the box
\n" ); document.write( "z is the right side of the box.
\n" ); document.write( "The perimeter is
\n" ); document.write( "The area is
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Algebra.Com's Answer #246845 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
Usually we talk about rectangles having length (shown as 'l') and width (shown as 'w'), so the P = 2l + 2w.\r
\n" ); document.write( "\n" ); document.write( "You have the values to substitute for 'l' and 'w'
\n" ); document.write( "\"l+=+z%2B2\"
\n" ); document.write( "\"w+=+z\"\r
\n" ); document.write( "\n" ); document.write( "\"P+=+2l+%2B+2w+=+2%2A%28z%2B2%29+%2B+2%2Az++=+2z+%2B+4+%2B+2z\"\r
\n" ); document.write( "\n" ); document.write( "Collecting terms, we have \r
\n" ); document.write( "\n" ); document.write( "\"P+=+4z+%2B+4\"\r
\n" ); document.write( "\n" ); document.write( "The area is found much the same way.\r
\n" ); document.write( "\n" ); document.write( "We know the area (A) of a rectangle = length times width = l * w.\r
\n" ); document.write( "\n" ); document.write( "Substituting what we know about l and w, we have:\r
\n" ); document.write( "\n" ); document.write( "\"A+=+%28z%2B2%29+%2A+z+=+z%5E2+%2B+2z\"\r
\n" ); document.write( "\n" ); document.write( "Done.
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