document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=344970>Question 344970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two vessels contains mixtures of alcohol and water. In one there is three times as much alcohol as water; in the other, five times as much water as alcohol. How much must be drawn off from each to fill a third vessel which holds 7 gallons, in order that its contents may be half water and half alcohol.\r<BR>\n" );
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document.write( "Thanks for the answer! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246843 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two vessels contains mixtures of alcohol and water.<BR>\n" );
document.write( " In one there is three times as much alcohol as water; in the other,<BR>\n" );
document.write( " five times as much water as alcohol.<BR>\n" );
document.write( "How much must be drawn off from each to fill a third vessel which holds 7<BR>\n" );
document.write( " gallons, in order that its contents may be half water and half alcohol. <BR>\n" );
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document.write( "Let x = amt drawn from the 1st vessel<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(7-x) = amt drawn from the 2nd vessel<BR>\n" );
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document.write( "Write an equation based on the percent alcohol<BR>\n" );
document.write( "In the 1st vessel 3 times as much alcohol as water = 75 % alcohol<BR>\n" );
document.write( "In the 2nd vessel 5 times as much water as alcohol = 16.7 % alcohol<BR>\n" );
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document.write( ".75x + .167(7-x) = .50(7)<BR>\n" );
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document.write( ".75x + 1.167 - .167x = 3.5<BR>\n" );
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document.write( ".750x - .167x = 3.5 - 1.167<BR>\n" );
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document.write( ".583x = 2.333<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.333%2F.583 ALIGN=MIDDLE  ALT=\"2.333%2F.583\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 4 gal from the 1st vessel<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3 gal from the 2nd vessel<BR>\n" );
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document.write( "Check in original equation<BR>\n" );
document.write( ".75(4) + .167(3) = .50(7)<BR>\n" );
document.write( "3 + .5 = 3.5<BR>\n" );
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