document.write( "Question 344990: two circles intersect and have a common chord that is 16cm long . the centers are 21cm apart . if the radius of one circle is 10cm ,find the radius of the other circle \n" ); document.write( "
Algebra.Com's Answer #246823 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "First we will assume the smaller circle is the one with radius 10. \n" ); document.write( "We will let the radius of the larger circle be r. We draw in a \n" ); document.write( "radius of each circle (in green): \n" ); document.write( " \n" ); document.write( "Then AC = 10, AB=21, BC = r, and CE = 8 since it is half of \n" ); document.write( "the common chord CD, which is 16.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Triangle ACE is a right triangle, so we can find AE by the Pythagorean \n" ); document.write( "theorem:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(We can see here that the larger circle could not have been the \n" ); document.write( "one with radius 10, for that would have made BE = 6 which would have \n" ); document.write( "been shorter than AE.)\r \n" ); document.write( "\n" ); document.write( "Therefore since AB = 21 and AE = 6\r \n" ); document.write( "\n" ); document.write( "AB = AE + EB\r \n" ); document.write( "\n" ); document.write( "21 = 6 + EB\r \n" ); document.write( "\n" ); document.write( "15 = EB\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Triangle CEB is a right triangle, so we can find r by \n" ); document.write( "the Pythagorean theorem\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Edwin \n" ); document.write( " |