document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39186>Question 39186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given f(x)=(x^3-4x^2+kx-2k)/ (x-5) find the value of k so that the remainder = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24681 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is probably done easiest by synthetic division...I do not know if you know of that, but here is how it goes<BR>\n" );
document.write( "5____1____-4_____k____-2k<BR>\n" );
document.write( "___________5_____5_____5k+25<BR>\n" );
document.write( "_____1_____1____k+5_____3k+25\r<BR>\n" );
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document.write( "It appears that the remainder would be zero if 3k + 25 = 0<BR>\n" );
document.write( "or k = -25/3\r<BR>\n" );
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document.write( "You could do this one by remainder theorem or by long division also. </SPAN>\n" );
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