document.write( "Question 344967: (x+5)(x+3)+5x+25=0 by factoring \n" ); document.write( "

Algebra.Com's Answer #246808 by jsmallt9(3758) $\"\"$ $\"About$

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$\"%28x%2B5%29%28x%2B3%29%2B5x%2B25=0\"$
\n" ); document.write( "The long way:
\n" ); document.write( "Simplify the left side:
\n" ); document.write( " $\"x%5E2+%2B8x+%2B15+%2B+5x+%2B+25+=+0\"$
\n" ); document.write( " $\"x%5E2+%2B+13x+%2B+40+=+0\"$
\n" ); document.write( "Factor:
\n" ); document.write( " $\"%28x%2B8%29%28x%2B5%29+=+0\"$
\n" ); document.write( "Solve:
\n" ); document.write( "From the Zero Product property we know that one of the factors must be zero:
\n" ); document.write( " $\"x%2B8+=+0\"$ or $\"x%2B5+=+0\"$
\n" ); document.write( "Solving these we get:
\n" ); document.write( " $\"x+=+-8\"$ or $\"x+=+-5\"$

\n" ); document.write( " $\"%28x%2B5%29%28x%2B3%29%2B5x%2B25=0\"$
\n" ); document.write( "The short way is based on noticing that (x+5) is already a factor of (x+5)(x+3) and that it is also a factor of 5x+25. This means we can factor by grouping:
\n" ); document.write( " $\"%28x%2B5%29%28x%2B3%29%2B5%28x%2B5%29+=+0\"$
\n" ); document.write( " $\"%28x%2B5%29%28%28x%2B3%29%2B5%29+=+0\"$
\n" ); document.write( " $\"%28x%2B5%29%28x%2B8%29+=+0\"$
\n" ); document.write( "And the rest is the same as the above. \n" ); document.write( "

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