document.write( "Question 4947: 5+w/5-w=3 \n" ); document.write( "
Algebra.Com's Answer #2468 by Abbey(339)\"\" \"About 
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multiply the equation by 5 to clear the denominator, your new equation is:
\n" ); document.write( "25+w-5w=15
\n" ); document.write( "consolidate like terms:
\n" ); document.write( "25-4w=15
\n" ); document.write( "subtract 25 from both sides:
\n" ); document.write( "-4w=-10
\n" ); document.write( "divide both sides by -4 and reduce:
\n" ); document.write( "\"w=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "verify by plugging it into the original equation:
\n" ); document.write( "\"5%2B%285%2F2%29%2F5-%285%2F2%29=15\"\r
\n" ); document.write( "\n" ); document.write( "This is a true statement, so w=5/2
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