document.write( "Question 344915: andrew can paint the neighbor's house 3 times as fast as bailey. the year they worked together it took them 2 days. how long would it take for each one to paint hte house alone? \n" ); document.write( "
Algebra.Com's Answer #246786 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! andrew can paint the neighbor's house 3 times as fast as bailey. \n" ); document.write( "--- \n" ); document.write( "Let bailey's time be 3x days/job ;then his rate is 1/3x job/day \n" ); document.write( "---------------------------- \n" ); document.write( "Andrew's time is x days/job ; andrew's rate is 1d/x job/day \n" ); document.write( "--------------------------------------\r \n" ); document.write( "\n" ); document.write( "the year they worked together it took them 2 days. \n" ); document.write( "Together time = 2 days/job ; together rate = 1/2 job/day \n" ); document.write( "------\r \n" ); document.write( "\n" ); document.write( " how long would it take for each one to paint the house alone? \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/3x + 1/x = 1/2 \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 6x to get: \n" ); document.write( "2 + 6 = 3x \n" ); document.write( "x = 8/3 days (time for andrew to do the job alone). \n" ); document.write( "3x = 8 days (time for bailey to do the job alone). \n" ); document.write( "======== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |