document.write( "Question 344866: how many grams of 4% salt solution must be mixed with 50g of a 9% salt solution to make a 6% salt solution? \n" ); document.write( "
Algebra.Com's Answer #246740 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many grams of 4% salt solution must \n" ); document.write( "be mixed with 50g of a 9% salt solution \n" ); document.write( "to make a 6% salt solution? \n" ); document.write( "-------------- \n" ); document.write( "Equation: \n" ); document.write( "salt + salt = salt \n" ); document.write( "0.04x + 0.09*50 = 0.06(x+50) \n" ); document.write( "-------- \n" ); document.write( "Multiply thru 100 to get: \n" ); document.write( "4x + 9*50 = 6x + 6*50 \n" ); document.write( "2x = 3*50 \n" ); document.write( "x = 75 grams (amt. of 4% solution needed for the mixture) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===============\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |