document.write( "Question 344836: 1. The perimeter of a rectangle is 32 inches, and the area is 60 square inches. find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #246714 by user_dude2008(1862)\"\" \"About 
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2L+2W=32 ----> L+W=16
\n" ); document.write( "LW=60 ----> L=60/W\r
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\n" ); document.write( "\n" ); document.write( "L+W=16\r
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\n" ); document.write( "\n" ); document.write( "60/W+W=16\r
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\n" ); document.write( "\n" ); document.write( "60+w^2=16w\r
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\n" ); document.write( "\n" ); document.write( "w^2-16w+60=0\r
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\n" ); document.write( "\n" ); document.write( "(w-10)(w-6)=0\r
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\n" ); document.write( "\n" ); document.write( "w-10=0 or w-6=0\r
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\n" ); document.write( "\n" ); document.write( "w=10 or w=6\r
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\n" ); document.write( "\n" ); document.write( "Answer: Width = 6 Length = 10
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