document.write( "Question 39247: can you please show me and explain EACH step in setting up and solving the following application problems. Give answers to the nearest thousandth if rounding is needed.\r
\n" ); document.write( "\n" ); document.write( "c. The length of a rectangle is 2 cm longer than its width. If the diagonal of the rectangle is 10cm. What are the dimensions (length and width) of the rectangle?
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Algebra.Com's Answer #24671 by Earlsdon(6294)\"\" \"About 
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Start with the Pythagorean theorem.
\n" ); document.write( "The diagonal (D) of a rectangle is the hypotenuse of a right triangle whose legs are the rectangle's length (L) and width (W). So we can write:\r
\n" ); document.write( "\n" ); document.write( "\"D%5E2+=+L%5E2+%2B+W%5E2\"\r
\n" ); document.write( "\n" ); document.write( "But we are also given that the length (L) is 2 cm longer than its width (W), so we can write: L = W+2 Substituting this into the above equation, we have:\r
\n" ); document.write( "\n" ); document.write( "\"D%5E2+=+%28W%2B2%29%5E2+%2B+W%5E2\" and we know that D = 10 cm, so...\r
\n" ); document.write( "\n" ); document.write( "\"10%5E2+=+%28W%2B2%29%5E2+%2B+W%5E2\" Simplify and solve for W.
\n" ); document.write( "\"100+=+W%5E2%2B4W%2B4%2BW%5E2\"
\n" ); document.write( "\"100+=+2W%5E2%2B4W%2B4\" Subtract 100 from both sides of the equation.
\n" ); document.write( "\"2W%5E2%2B4W-96+=+0\" Divide both sides by 2 to simplify.
\n" ); document.write( "\"W%5E2%2B2W-48+=+0\" Factor the quadratic equation.
\n" ); document.write( "\"%28W-6%29%28W%2B8%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"W-6+=+0\" and/or \"W%2B8+=+0\"
\n" ); document.write( "If \"W-6+=+0\" then \"W+=+6\"
\n" ); document.write( "If \"W%2B8+=+0\" then \"W+=+-8\" Discard this solution as the width must be a positive number.\r
\n" ); document.write( "\n" ); document.write( "The width is 6 cm.
\n" ); document.write( "The length is width + 2 cm = 6 + 2 = 8 cm.
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