document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39240>Question 39240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one side of a rectangle is sqrt 3 + sqrt 5, and the second side is sqrt 3 + sqrt 5, find the area of the rectangle.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24670 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for the area of a rectangle is<BR>\n" );
document.write( "A = LW<BR>\n" );
document.write( "Here it appears that L and W are equal, so we actually have a square.  No matter, we still multiply L and W...<BR>\n" );
document.write( "A = (sqrt 3 + sqrt 5)(sqrt 3 + sqrt 5) =<BR>\n" );
document.write( "A = 3 + sqrt(15) + sqrt(15) + 5 =<BR>\n" );
document.write( "A = 8 + 2*sqrt(15) </SPAN>\n" );
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