document.write( "Question 39246: Show EACH step in solving each of the following equations. State if any solution is extraneous.
\n" ); document.write( "a. sqrt(3x + 1) = 4
\n" ); document.write( "b. 2x - sqrt(3x - 2) = 8
\n" ); document.write( "c. sqrt(2x - 1) = x - 8
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Algebra.Com's Answer #24667 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a. sqrt(3x + 1) = 4
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "3x+1=16
\n" ); document.write( "3x=15
\n" ); document.write( "x=5\r
\n" ); document.write( "\n" ); document.write( "b. 2x - sqrt(3x - 2) = 8
\n" ); document.write( "Rewrite as sqrt(3x-2)=2x-8
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "3x-2=4x^2-32x+64
\n" ); document.write( "4x^2-35x+66=0
\n" ); document.write( "Solve for \"x\" as follows:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"4x%5E2%2B-35x%2B66+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-35%29%5E2-4%2A4%2A66=169\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=169 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--35%2B-sqrt%28+169+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%28-35%29%2Bsqrt%28+169+%29%29%2F2%5C4+=+6\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-35%29-sqrt%28+169+%29%29%2F2%5C4+=+2.75\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"4x%5E2%2B-35x%2B66\" can be factored:
\n" ); document.write( " \"4x%5E2%2B-35x%2B66+=+4%28x-6%29%2A%28x-2.75%29\"
\n" ); document.write( " Again, the answer is: 6, 2.75.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B-35%2Ax%2B66+%29\"

\n" ); document.write( "\n" ); document.write( "The solutions x=6 or x=2.75 are both valid.
\n" ); document.write( "c. sqrt(2x - 1) = x - 8
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "2x-1=x^2-16x+64
\n" ); document.write( "x^2-18x+65=0
\n" ); document.write( "Solve for \"x\" as follows:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-18x%2B65+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-18%29%5E2-4%2A1%2A65=64\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=64 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--18%2B-sqrt%28+64+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%28-18%29%2Bsqrt%28+64+%29%29%2F2%5C1+=+13\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-18%29-sqrt%28+64+%29%29%2F2%5C1+=+5\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"1x%5E2%2B-18x%2B65\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-18x%2B65+=+1%28x-13%29%2A%28x-5%29\"
\n" ); document.write( " Again, the answer is: 13, 5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-18%2Ax%2B65+%29\"

\n" ); document.write( "\n" ); document.write( "The solutions x=13 or x=5 are both valid.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \r
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