document.write( "Question 344685: If a+b=9 and a^3+b^3=351, find the numerical value of ab \n" ); document.write( "
Algebra.Com's Answer #246633 by Jk22(389)\"\" \"About 
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(a+b)^3=a^3+3a^2b+3ab^2+b^3=351+3ab(a+b)=351+3ab*9=9^3=81*9=729
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\n" ); document.write( "hence 27ab=729-351=378
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\n" ); document.write( "ab=126/9=42/3=14
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