document.write( "Question 344507: An unbalanced but otherwise standard 6-faced die is rolled. The probability of getting a 1 is four times the probability of getting any other number. Find the probability of getting an even number.\r
\n" ); document.write( "\n" ); document.write( "So I get that we need to find the probability of getting a 2, 4, OR 6, because they are the even numbers. Normally the prob. would be 1/6 for each and you would add them together.....but I am confused because the prob. of getting a 1 is four times greater...? Please help! \n" ); document.write( "
Algebra.Com's Answer #246632 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
An unbalanced but otherwise standard 6-faced die is rolled.
\n" ); document.write( "The probability of getting a 1 is four times the probability of getting any other number.
\n" ); document.write( "4x+5(x) = 1
\n" ); document.write( "9x = 1
\n" ); document.write( "x = 1/9
\n" ); document.write( "P(1) = 4/9
\n" ); document.write( "P(2) = 1/9
\n" ); document.write( "P(3) = 1/9
\n" ); document.write( "P(4) = 1/9
\n" ); document.write( "P(5) = 1/9
\n" ); document.write( "P(6) = 1/9
\n" ); document.write( "-----------------------------\r
\n" ); document.write( "\n" ); document.write( "Find the probability of getting an even number.
\n" ); document.write( "P(2 or 4 or 6) = 3/9 = 1/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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