document.write( "Question 344674: Hi I don't know how to solve the following :
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document.write( "1.e^(2lnx+lny)
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document.write( "2. ln square root sign(e^x+y)
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document.write( "3.log to the base 3 - log3 (2-3x)= log9 (6x^2-19x+2)
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document.write( "4. simultaneous equations :
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document.write( " I) log2X (log 2 to the base x) - log4y (log 4 to the base y ) =4
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document.write( " and log2(x-2y)(log 2 to the base x-2y)=5 \n" );
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Algebra.Com's Answer #246630 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1.e^(2lnx+lny) \n" ); document.write( "= e^(ln(x^2)+ln(y) \n" ); document.write( "--- \n" ); document.write( "= e^(ln(x^2*y)) \n" ); document.write( "--- \n" ); document.write( "= x^2*y \n" ); document.write( "====================\r \n" ); document.write( "\n" ); document.write( "2. ln square root sign(e^x+y) \n" ); document.write( "--- \n" ); document.write( "= ln[e^(x+y)]^(1/2) \n" ); document.write( "--- \n" ); document.write( "= (1/2)*ln(e^(x+y)) \n" ); document.write( "--- \n" ); document.write( "= (1/2)(x+y) \n" ); document.write( "====================\r \n" ); document.write( "\n" ); document.write( "3.log to the base 3 - log3 (2-3x)= log9 (6x^2-19x+2) \n" ); document.write( "Something is missing in your problem statement. \n" ); document.write( "================================================\r \n" ); document.write( "\n" ); document.write( "4. simultaneous equations : \n" ); document.write( "I) log2X (log 2 to the base x) - log4y (log 4 to the base y ) =4 \n" ); document.write( "and log2(x-2y)(log 2 to the base x-2y)=5 \n" ); document.write( "--- \n" ); document.write( "log2(x)-log2(y) = 4 \n" ); document.write( "log2(x-2y) = 5 \n" ); document.write( "------ \n" ); document.write( "log2(x/y) = 4 \n" ); document.write( "log2(x-2y) = 5 \n" ); document.write( "------- \n" ); document.write( "x/y = 2^4 \n" ); document.write( "x-2y = 2^5 \n" ); document.write( "------- \n" ); document.write( "x -16y = 0 \n" ); document.write( "x -2y = 32 \n" ); document.write( "----- \n" ); document.write( "Subtract 1st from 2nd and solve for \"y\": \n" ); document.write( "14y = 32 \n" ); document.write( "y = 16/7 \n" ); document.write( "---- \n" ); document.write( "Since x/y = 16 \n" ); document.write( "x = 16y = 16(16/7) = 16^2/7 \n" ); document.write( "-------- \n" ); document.write( "Solution: x = 16/7 ; y = 16^2/7 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |