document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=344661>Question 344661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you have one gallon of pure antifreeze, how much water would you add to make a mixture of 70 percent water and 30 percent antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #246608 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=246608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 gallon (antifreeze) -> 30<BR>\n" );
document.write( "then 70 (water) -> x gallon water ?, x=70/30*1 gallon=7/3 gallon water which is approx : 2,33 gallon water. </SPAN>\n" );
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