document.write( "Question 344643: If Ben invests $4000 at 3% interest per year, how much additional money must he invest at 4.5% annual interest to ensure that the interest he receives each year is 3.5% of the total amount invested? \n" ); document.write( "
Algebra.Com's Answer #246582 by mananth(16946)![]() ![]() You can put this solution on YOUR website! $4000 @ 3 % Interest = $120 \n" ); document.write( ".. \n" ); document.write( "Let him invest $ x @ 4.5% \n" ); document.write( "interest he will get on this amount = x*0.045*1 \n" ); document.write( "=0.045x \n" ); document.write( ".. \n" ); document.write( "Total interest will be 120 + 0.045x.............1 \n" ); document.write( ".... \n" ); document.write( "Total amount invested = 4000+x \n" ); document.write( "interested desired = 3.5% \n" ); document.write( "= 0.035*(4000+x ) ........................2 \n" ); document.write( "... \n" ); document.write( "equate 1 &2 \n" ); document.write( "120+0.045x =0.035(4000+x) \n" ); document.write( "120+0.045x=140+0.035x \n" ); document.write( "0.045x-0.035x=140-120 \n" ); document.write( "0.01x= 20 \n" ); document.write( "/0.01 \n" ); document.write( "x=20/0.01 \n" ); document.write( "x= $2000 . investment @ 4.5% \n" ); document.write( " |